Proyectos

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spktz v81.4
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App debug
App errors
Async debug
Async errors
Sql stack
Config
Async network
Server console
  1. SQL: [70] SELECT * FROM procategorie WHERE deleted=0 ORDER BY categorieOrder ASC
  1. SQL: [67] SELECT * FROM proservices WHERE deleted=0 ORDER BY serviceOrder ASC
  1. SQL: [123] SELECT pp.* FROM proproject AS pp  WHERE  pp.deleted = 0 AND pp.enabled = 1  ORDER BY pp.proOrder ASC LIMIT 14, 14
  1. SQL: [95] SELECT COUNT(pp.id) as 'total' FROM proproject AS pp  WHERE  pp.deleted = 0 AND pp.enabled = 1 
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=16
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=16
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=234
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=234
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=17
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=17
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=203
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=203
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=3
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=3
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=19
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=19
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=93
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=93
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=20
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=20
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=147
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=147
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=21
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=21
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=217
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=217
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=23
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=23
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=190
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=190
  1. SQL: [175] SELECT pc.id, pc.nameES, pc.nameEN FROM procategorie AS pc INNER JOIN proprojectcategories as ppc ON (pc.id = ppc.idCategorie) WHERE pc.deleted = 0 AND ppc.idProject=24
  1. SQL: [184] SELECT pc.id, pc.nameES, pc.nameEN FROM prosubcategorie AS pc INNER JOIN proprojectsubcategories as ppc ON (pc.id = ppc.idSubcategorie) WHERE pc.deleted = 0 AND ppc.idProject=24
Control: index
App: projects/project
AppFolder: gomezplatero
Core:
AppId:
Php:
Build:
Server time:
Test:
Theme: web
ViewParser:
Request URI: /gomezplatero/es/proyectos/2/
Params: Env params
0 => es/proyectos/2/
lang => es
1 => es
page => 2
2 => 2
Spktoolz path missing.